You accidentally end up in the top secret lab of an eccentric candy factory. Can you win Billy Bonka’s game and get set free?
—
You’re on a tour of the eccentric Billy Bonka’s mysterious candy factory, when a wrong turn searching for the restroom lands you in the top secret candy laboratory. Enraged at your trespassing, Bonka explains that the consequences are simple: you must play his game. You lose, and he’ll throw you into his Chew-o-meter 3000. Can you outsmart Billy Bonka’s challenge? Edwin F. Meyer shows how.
Lesson by Edwin F. Meyer, directed by Igor Ćorić, Artrake Studio.
Support Our Non-Profit Mission
———————————————-
Support us on Patreon:
Check out our merch:
———————————————-
Connect With Us
———————————————-
Sign up for our newsletter:
Follow us on Facebook:
Find us on Twitter:
Peep us on Instagram:
———————————————-
Keep Learning
———————————————-
View full lesson:
Dig deeper with additional resources:
Animator’s website:
———————————————-
Thank you so much to our patrons for your support! Without you this video would not be possible! Sandra Tersluisen, Zhexi Shan, Bárbara Nazaré, Andrea Feliz, Victor E Karhel, Sydney Evans, Latora, Noel Situ, emily lam, Sid, Niccolò Frassetto, Mana, I’m here because of Knowledge Fight Facebook group., Linda Freedman, Edgardo Cuellar, Jaspar Carmichael-Jack, Michael Burton, VIVIANA A GARCIA BESNE, The Vernon’s, Olha Bahatiuk, Jesús Bíquez Talayero, Chels Raknrl, Sai Pranavi Jonnalagadda, Stuart Rice, Jing Chen, Vector-Dopamine math, Jasper Song, Giorgio Bugnatelli, Chardon, Eddy Trochez, OnlineBookClub.org, Eric Shear, Leith Salem, Omar Hicham, Adrian Rotaru, Brad Sullivan, Karen Ho, Niklas Frimberger, Hunter Manhart, Nathan Nguyen, Igor Stavchanskiy, James R DeVries, Grace Huo, Diana Huang, Chau Hong Diem, Orlellys Torre, Corheu, Thomas Mee, Maryann H McCrory, and Blas Borde.
source
Now that you’re warmed up, shift your brain into high gear with Rush Hour — a new take on a classic puzzle. Simple rules, surprisingly tricky solutions. Check it out at ted.com/games
Finally!
Finally!!
This is child's play compared to my riddles
I just wanted to find the bathroom. Now my survival depends on math. Worst factory tour ever 😂
Silly Zonka Wonka
This answer is WRONG!
It was determined that #3 was yes/red. Not yes/white. If #4 and #5 are blue and red (or vice versa), #3 would be no/either red or white. With #2 and #3 being logically deduced to yes/red. That leaves #4 and #5 to be blue/white, white/blue, or white/white. Which results in #5 as no/blue or white. If we insist that there is a forced logical conclusion, then we must pick #4 and #5 to be logically deduced to be white/white. The alternative would be a coin flip whether to make #4 and #5 blue/white or white/blue.
I didn't read all the comments, so, excuse me if someone already pointed this out.
So thrilled to see another TED-Ed riddle!
Go Go Copyrighted Character
who up bonking they billy rn
But the real question, did I ever get to use the restroom?
1:54 ok time to try this on my own.
The back response is most important as he sets the initial lay out. It's minimal but enough. In order for him to say yes he would need specifically 4 red knowing he must be white, or 2 white and 1 blue knowing he must be red, or 2 red, a white, and a blue knowing he must be white. Making these states impossible. Meaning 1 red needed to be taken. And his lack of knowledge is only possible if he sees more than 1 color, and not all of a color that is on the board. Knowing at least 1 red needed to be taken not to confirm his game state, he does not see 3 red and 1 color. Likely meaning he sees 2 red and each color. Making him red or white.
The second, has to see something to confirm his own game state. Knowing the count from the back. He knows there are 2 red, 1 white, and 1 blue in front of the back. To confirm his own color he can pretty much just take that number out of what he sees.
The third now knows what he is. If he sees 2 reds, he is in a toss up making him red. This is where i start feeling like I'm losing the game as this splits the board into all 3 colors between him, the last helper, and you. This would be impossible for the 4th to know without an indicator.
The fourth knows you are a different color from him, and he is a different color from the guy behind him. In order for this to not be a toss up he has to somehow know the color of the guy behind him. That's as far as I'm getting as I'm likely missing a detail.
Edit: ok i should have written the permutations down, i missed the other places that would cause ambiguity. But I'm glad to see that even with a linear stream of thought i got close.
The quote at the beginning is actually from "The Microbe" by Hillaire Belloc. Most lines from the film are literary quotes.
While I like the riddle, I find the presentation of "eleminate options from a table" approach hard to follow without pen and paper. Here's the same chain of thought, expressed in a way that's hopefully easier to follow without needing to take notes:
– PB1 is uncertain of their hair colour. If they saw both whites and the blue before them, they would know theirs is red. Thus, at least two of the last 4 have red hair.
– PB2 knows their hair colour. If they saw two or more reds, they'd be uncertain. Thus, they must see exactly one red and know that they're one of the reds that PB1 saw. This leaves two options for the final 3: rww or rwb.
– PB3 cannot see white and red, as they could then either be blue or white themselves. They also can't see two blues (there's only one) or two reds (PB2 wouldn't have been certain). The other options uniquely define PB3 as either red (they see ww or bw) or white (they see br).
PB4 now considers their options:
– If PB4 sees white, PB3 must've been red. But looking at the previous options, PB4 could be white or blue in this case. Out.
– If PB4 sees blue, they could be red or white (same argument). Out.
Thus PB4 sees red, which is your hair colour.
My solution:
PB1 can only be sure if he can eliminate two colours, meaning he would see 2 white, 1 blue and only 1 red. Since he is not sure, he sees at least 2 reds.
This only helps PB2 if he sees exactly 1 red, otherwise this does not tell him anything. He therefore deduces his hair is red. Also, out of the remaining three there is one person with red hair and two with non-red hair.
PB3, knowing this and seeing the remaining two, now knows whether he himself has red or non-red hair.
If the player would have blue hair, then PB3 and PB4 would be red/white or white/red (only one blue maximum). PB3 would know, but PB4 would have no chance to find out (and could therefore not say yes).
If the player would have white hair, PB3 could only say yes if he was sure his hair was red, otherwise he could not distinguish between having blue hair or white hair. In that case, PB4 would know he had non-red hair, but he again could not distinguish between having white or blue hair and could not say yes.
Therefore the player has red hair.
You don't even need to find all the exact hair colours to solve the riddle.
I got it right, phew 😊
It took me the best part of an hour, but I reasoned it out.
4:14 – Freezing the screen at 4:14, I see a lot that is omitted. The 2nd creature to call out (2nd from left) can, in the top row, can verify that he is not blue, because the tourist is blue, and there is only one blue. He can verify that he is not white, because if he were white, there would be, counting himself, two whites and one blue ahead of the 1st (far left) creature to call out, and that creature would have been certain that he the 1st creature) was red because if he were white there'd be three whites (and there are at most two whites) and if he were blue there'd be two blues (and there is at most one blue. So the 2nd creature knows that he (2nd) is not white. He also knows he is not blue because the tourist is blue and he knows there is at most one blue. So, in this top row, he knows he's red.
Now let's go to the 2nd row. He sees two whites in front of him, so if he were blue the 1st creature would have seen a blue and two whites and would have known that he (1st) was red. But he didn't know. So the 2nd creature knows he is not blue. And he knows he's not white because he can see two whites and he knows there are at most two whites. So he knows he is red. Either way, top row or bottom row, he knows he is red, and the tourist knows WHY he knows he is red.
This is all correct, but it's been left out entirely.
is it just me? the 3 and 4 feel less like logical reasoning and more like bruteforcing the rest of the possibilities. having to follow 2 possible logical conclusions makes this way to cerebral. not really fun to solve
I’ve been watching these riddles since they came out and this is the first riddle. I got right!!!!!!!🎉🎉
Oh god not again
First, confirm you have green eyes